From: FMJD annexes, 5.11.1.2.1. For round robin tournaments (p31)
- "the best results obtained in order of the classification"
We can rephrase the definition based on game points per same score group.
The same score groups are ranked from high to low, in this example: +2, +1, 0, -1, -2, -3.
The new order will be:
- Better results grouped by the same score, in descending order
Example DraughtsArbiter Pro (v.5.44b1)
Why are players 1,2 and 3, 4 tied?
Pl Name |1 2 | 3 4 | 5 6 | ± Pt No O.(W) 1 H1 |X 1 | 1 2 | 2 1 | +2 7 7.05 ????? 1 H2 |1 X | 2 1 | 1 2 | +2 7 7.05 3 M1 |1 0 | X 1 | 2 1 | =0 5 5.07 ????? 3 M2 |0 1 | 1 X | 1 2 | =0 5 5.07 5 L1 |0 1 | 0 1 | X 2 | -1 4 6 L2 |1 0 | 1 0 | 0 X | -3 2
Calculation per same score group (±)
Pl Name | +2 | =0 |-1 -3 | ± Pt Key TB 1 H1 | 1 | 3 | 2 1 | +2 7-1321 1 2 H2 | 1 | 3 | 1 2 | +2 7-1312 2 3 M1 | 1 | 1 | 2 1 | =0 5-1121 3 4 M2 | 1 | 1 | 1 2 | =0 5-1112 4 5 L1 | 1 | 1 | 0 2 | -1 4-1102 5 6 L2 | 1 | 1 | 0 0 | -3 2-1100 6
Example Direct Encounter
Sort Criteria for tie-break rules, point 5.
Better score between 2 (or more) players at the shared places
A, B, C are tied at places 2 to 4 with total score = 4.
Direct encounter score A = 3, B=1, C = 2.
Why are players B, C tied as shown below?
- Total Score
- Direct Encounter
Example World Championship 2025 - Final Yaoundé
Pl Naam Rating 1 2|3 4|5 6 7 8 9|A B C N ± = - Pt 1 Jan Groenendijk GMI 2442 X 1 1 1 2 1 1 1 1 1 2 1 11 +2 9 0 13 2 Jitse Slump GMI 2409 1 X 1 1 1 1 2 1 1 1 1 2 11 +2 9 0 13 3 Guntis Valneris GMI 2404 1 1 X 1 1 1 1 1 1 2 1 1 11 +1 10 0 12 4 M. van IJzendoorn GMI 2384 1 1 1 X 1 1 1 1 1 2 1 1 11 +1 10 0 12 5 N`cho Joel Atse GMI 2352 0 1 1 1|X 1 1 2 1|1 1 1 11 =0 9 1 11 6 Kees Thijssen GMI 2337 1 1 1 1|1 X 1 1 1|0 1 2 11 =0 9 1 11 7 Wouter Sipma GMI 2372 1 0 1 1|1 1 X 1 1|1 1 2 11 =0 9 1 11 8 Martin Dolfing GMI 2344 1 1 1 1|0 1 1 X 1|1 2 1 11 =0 9 1 11 9 M.R. Lutete GMI 2317 1 1 1 1|1 1 1 1 X|1 1 1 11 =0 9 0 11 10 Ron Heusdens GMI 2258 1 1 0 0 1 2 1 1 1 X 1 1 11 -1 8 2 10 11 Emre Hageman MI 2223 0 1 1 1 1 1 1 0 1 1 X 1 11 -2 9 2 9 12 Simon Harmsma MI 2286 1 0 1 1 1 0 0 1 1 1 1 X 11 -3 8 3 8
Calculation per same score group (±)
Pl Naam Rating +2 +1 0-1-2-3 N ± = - Pt Key TB 1 Jan Groenendijk GMI 2442 1| 2| 6|1 2 1|11 +2 9 0 13-126121 1 2 Jitse Slump GMI 2409 1| 2| 6|1 1 2|11 +2 9 0 13-126112 2 3 Guntis Valneris GMI 2404 2| 1| 5|2 1 1|11 +1 10 0 12-215211 4 4 M. van IJzendoorn GMI 2384 2| 1| 5|2 1 1|11 +1 10 0 12-215211 4 5 N`cho Joel Atse GMI 2352 1| 2| 5|1 1 1|11 =0 9 1 11-125111 8 6 Kees Thijssen GMI 2337 2| 2| 4|0 1 2|11 =0 9 1 11-224012 6 7 Wouter Sipma GMI 2372 1| 2| 4|1 1 2|11 =0 9 1 11-124112 9 8 Martin Dolfing GMI 2344 2| 2| 312 1 1|11 =0 9 1 11-223211 7 9 M.R. Lutete GMI 2317 2| 2| 4|1 1 1|11 =0 11 0 11-224111 5 10 Ron Heusdens GMI 2258 2| 0| 5|X 1 1|11 -1 8 2 10-205011 10 11 Emre Hageman MI 2223 1| 2| 4|1 0 1|11 -2 9 2 9-124101 11 12 Simon Harmsma MI 2286 1| 2| 3|1 1 0|11 -3 8 3 8-123110 12
